![100 mL of 0.1 N NaOH solution is required neutralization of 0.49 g of a dibasic acid. What is the molecular weight of the acid? (a) 49 (b) 98 (c) 490 (d) 196 100 mL of 0.1 N NaOH solution is required neutralization of 0.49 g of a dibasic acid. What is the molecular weight of the acid? (a) 49 (b) 98 (c) 490 (d) 196](https://toppr-doubts-media.s3.amazonaws.com/images/8116150/233ceaf6-f22c-41a9-a57b-9cd4f408a6d1.jpg)
100 mL of 0.1 N NaOH solution is required neutralization of 0.49 g of a dibasic acid. What is the molecular weight of the acid? (a) 49 (b) 98 (c) 490 (d) 196
![1N NaOH – Select A Size – Vinmetrica – Sulfite (SO2), Malic, Alcohol & pH/TA tests for Wine, Beer & Kombucha. 1N NaOH – Select A Size – Vinmetrica – Sulfite (SO2), Malic, Alcohol & pH/TA tests for Wine, Beer & Kombucha.](https://vinmetrica.com/wp-content/uploads/2015/03/DSC1484-scaled.jpg)
1N NaOH – Select A Size – Vinmetrica – Sulfite (SO2), Malic, Alcohol & pH/TA tests for Wine, Beer & Kombucha.
100ml 0.5N NaOH is mixed in 10ml of 3N H2SO4 and 20 ml of 1N HCl solution. This mixture is not acid and base why?
![How to prepare 0.1 N NaOH solution | 250 ml of 0.1 N NaOH solution | 0.1 N NaOH solution calculation - YouTube How to prepare 0.1 N NaOH solution | 250 ml of 0.1 N NaOH solution | 0.1 N NaOH solution calculation - YouTube](https://i.ytimg.com/vi/-kTkTlH4WoA/hqdefault.jpg)
How to prepare 0.1 N NaOH solution | 250 ml of 0.1 N NaOH solution | 0.1 N NaOH solution calculation - YouTube
![SOLVED: Title: Calculation of Amount of NaOH for 1N Solution Text: 1N NaOH Solution Homework Why have you used 4.5 g of NaOH to prepare 100 mL of 1N NaOH solution? SOLVED: Title: Calculation of Amount of NaOH for 1N Solution Text: 1N NaOH Solution Homework Why have you used 4.5 g of NaOH to prepare 100 mL of 1N NaOH solution?](https://cdn.numerade.com/ask_images/61b5527328cc4678b695f77b29851dc3.jpg)
SOLVED: Title: Calculation of Amount of NaOH for 1N Solution Text: 1N NaOH Solution Homework Why have you used 4.5 g of NaOH to prepare 100 mL of 1N NaOH solution?
![61. The volume of 0.1 M NaOH required to neutralize 10 mL of 0.1 M HCI (A) 10 mL (B) 20 mL (C) 5 mL (D) 15 mL 000 Sa Id=18 almal hy weight is 61. The volume of 0.1 M NaOH required to neutralize 10 mL of 0.1 M HCI (A) 10 mL (B) 20 mL (C) 5 mL (D) 15 mL 000 Sa Id=18 almal hy weight is](https://toppr-doubts-media.s3.amazonaws.com/images/8596650/c38504df-dc9a-4970-8dca-e6eb2c43b971.jpg)